1. Describe the rotation that has taken place in the triangle below.
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A= 16π cm2find radius then circumferencea=pir^216pi=pir^2divide pi16=r^2r=4circuumfrence=2pircircumfernce=2pi4c=8piok so the angle is 3pi radianscircle is 2piradians so  3pi/2pi=3/2arec leanth is 3/2 of circumfernce3/2 times 8pi=(24pi)/2=12pianswer is 12pi cm (unless i misread the question and the values given)