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bikkiecuanas13
05.09.2019 •
Mathematics
1. for g(x) = 4x - 9, find g(x) when x = 0 and when x = 1
2. for h(t) = 1/3t - 10, find h(t) when t = 27 and when t = -15
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Ответ:
Part A: (2x−5)(x+2)
Part B: (5/2,0) and (-2,0)
Part C: The graph of f(x) has both "ends" of the graph pointing upward. You can describe this as heading toward infinity.
Part D: To graph function we can use x-intercepts and "ends" to sketch.In order to graph better use one more point of parabola that you can find as the average of x-intercepts: (-2+5/2)/2 =1/4.This is just x coordinate and you need to plug in 1/4 in the f(x) and find y coordinate -10 1/8. You can use y-intercept (0,-10) as well to graph.
Step-by-step explanation:
Part A:![2x^{2} -x-10 =(2x - 5)(x+2)](/tpl/images/0663/2595/bcc80.png)
What 2 numbers when multiplied give -20 and when added up -1. Numbers are -5 and 4.
Rewrite quadratic expression as![2x^{2} -5x +4x -10](/tpl/images/0663/2595/79387.png)
Factor by grouping![x(2x-5)+2(2x-5)](/tpl/images/0663/2595/fa053.png)
Part B: x- intercepts are found when (2x−5)(x+2) = 0
Set factors equal to 0.
2x−5=0 or x+2=0
x=5/2 or x=−2
Part C: The lead coefficient (multiplier on the
) is a positive number, which causes the parabola to open upward.The first graph of
has both "ends" of the graph pointing upward so this can be described as heading toward infinity.
Part D: