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cutegirl0987
03.11.2020 •
Mathematics
1. Given s = 3x +t/r
rearrange the equation for x, in terms of r, s, and t
2. Given 5ax + b = C, rearrange the equation for x, in terms of a, b, and c.
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Ответ:
Step-by-step explanation:
1). s =![\frac{3x+t}{r}](/tpl/images/0862/4235/10e0e.png)
r.(s) =![r.(\frac{3x+t}{r})](/tpl/images/0862/4235/b857e.png)
rs = 3x + t
rs - t = 3x
2). 5ax + b = c
(5ax + b) - b = c - b
5ax = c - b
x =![\frac{1}{5}(\frac{c-b}{a})](/tpl/images/0862/4235/4c342.png)
Ответ:
The factored form of given polynomial is![x^3(4x^2-5x-9)](/tpl/images/0060/5125/6e077.png)
Step-by-step explanation:
Given the polynomial![4x^5 - 20x^4 - 36x^3](/tpl/images/0060/5125/bcc4a.png)
We have to factor the above polynomial completely.
Take
common from each term.
Here, the quadratic polynomial is prime i.e it cannot be factored into lower degree polynomial. It has complex roots.
Hence, the factored form of given polynomial is![x^3(4x^2-5x-9)](/tpl/images/0060/5125/6e077.png)