1) if p(x,-8) is a point on the line y=3x-2 what are the coordinates of p? 2) if q(2,y) is a point on the line y=3x-2. what are the coordinates of q?

For part one, this means that the y value (the second value) is -8, and since we know that y=3x-2, we can say that -8=3x-2.
Adding 2 to both sides using the addition property of equality, we get -6=3x. Next, dividing by 3 using the division property of equality, we get -2=x. Therefore, plugging -2 in the point, we get (-2,-8) as our point.

For the second point, we have 2 as the x value, so we can plug that into 3x-2 to get 3*(2)-2=6-2=4 as the y value, making the point (2,4)

Feel free to ask further questions!

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Step-by-step explanation:

perform multiplication and division first, working from left to right, before doing addition and subtraction.

First solve parenthesis: (also solve 4^2)

4^2 + (10 - 2 × 3) ÷ 4

16 + (10 - 6) ÷ 4

16 + 4 ÷ 4

16 + 1

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