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caleb3989
18.04.2020 •
Mathematics
(1) Let {v1,v2,v3} be a set of vectors in Rn . If u is Span {v1,v2,v3}, show that 3u is in Span {v1,v2,v3}.
(Hint: since you are told that u is in the span {v1,v2,v3}, you can automatically say that there are scalars c1,c2 and c3 so that u = c1v1+c2v2+c3v3. Your goal now is to find a way to write 3u as a linear combination of {v1,v2,v3}
(2) Let u, v1,v2,v3 and v4 be vectors in the Rn . If u can be written as a linear combination of v1,v2, and v3 show that u can also be written as a linear combination of v1,v2,v3 and v4 .
(Hint: Look at the previous question and remember you can use 0 as a coefficient in your equation.)
(3) Let u, v, w1, w2, and w3 be vectors in the Rn. If u and v can both be written as linear combinations of w1, w2 and w3 show that u+v can also be written as a linear combination of w1, w2, and w3.
(hint:this is similar to the previous ones. Remember to choose different letters for your coefficients for u and v)
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Ответ:
(1)
Multiplying by 3 both sides of the equality you get that
3u is in the Span of the vectors
.
(2)
That's not true, consider the following counter example.
Step-by-step explanation:
(1)
As the hint indicates, you know that
Then, if you multiply both sides of the equality by 3, you get that
And that's it. 3u is in the Span of the vectors![\{v_1,v_2,v_3\}](/tpl/images/0610/1029/85caf.png)
(2)
That's not true, consider the following counter example.
Ответ:
10.51
Step-by-step explanation:
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