jrjimenez
06.02.2021 •
Mathematics
1. Quadrilateral EFGH has vertices at E(1,8), F(6,-1), G(-4,-4) and H(-9,5).
(a) Prove that EFGH is a parallelogram.
(b) Prove that EFGH is not a rhombus (many methods)
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Ответ:
Step-by-step explanation:
It's C.
8x8 = 64,
64/8 = 8