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kenny909
19.09.2019 •
Mathematics
1.
what are the x-intercepts of the quadratic function?
f(x)=x^2+2x−24
? and ?
2.
let f(x)=x^2+17x+72
what are the zeros of the function?
? and ?
3.
let f(x)=x^2+6x+11 .
what is the minimum value of the function?
?
Solved
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Ответ:
x intercept is where y=0 let f(x)=y
x^2+2x−24=0
(x+6)(x-4) ,x=-6, x=4
2)
f(x)=x^2+17x+72
x^2+17x+72 =0
(x+8)(x+9) x= - 8,- 9
3)
f(x)=x^2+6x+11
x=-3 minimum
Ответ: