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ReignAsrs
27.06.2019 •
Mathematics
1. write an equation in slope intercept form for the line that passes through (-2,2) and is parallel to 2x+4y= 16 2. write an equation in slope intercept form for the line that passes through (4,1) and is perpendicular to 4x -y=3
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Ответ:
The equation of this line would be y = -1/2x + 1
Step-by-step explanation:
In order to find this equation we must first find the slope of the original line. To do this, we need to solve the original equation for y.
2x + 4y = 16
4y = -2x + 16
y = -1/2x + 4
The original slope (the coefficient of x) is -1/2, which means the new slope will also be -1/2 because parallel lines have the same slope. Now, we can use this slope along with the point in point-slope form to find the equation of the line.
y - y1 = m(x - x1)
y - 2 = -1/2(x + 2)
y - 2 = -1/2x - 1
y = -1/2x + 1
Ответ:
hi there
Step-by-step explanation: