Mathematics: (1/(x-/(x^2+2x-3))[tex] rac{1}{x - 1} - rac{3}{x {}^{2} + 2x - 3 } [/tex]

(1/(x-/(x^2+2x-3))[tex] \frac{1}{x - 1} - \frac{3}{x

Ответ:

xojade

09.03.2022

$\dfrac{1}{x-1}-\dfrac{3}{x^2+2x-3} \\\dfrac{1}{x-1}-\dfrac{3}{(x+3)(x-1)} \\\dfrac{1\cdot(x+3)-3}{(x+3)(x-1)} \\\dfrac{x+3-3}{(x+3)(x-1)} \\\dfrac{x}{(x+3)(x-1)}$

Hope this helps.

r3t40

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Ответ:

oVcper

27.09.2021

Mathematics

24960 dollars per year

Step-by-step explanation:

(450 + 30) x 52 ( weeks in a year)

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(1/(x-/(x^2+2x-3)) $\frac{1}{x - 1} - \frac{3}{x {}^{2} + 2x - 3 }$

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