10 different names are in a computer and one is Collin on Saturday, the computer choses 2 names at random. the computer is set so the same name can be chosen twice
what is the probability that Collin is chosen at least once

 700.22 dollars

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Explanation:

The formula given is

which to be honest is a big ugly mess of variables. The fractions also make things even more messy. Through trial and error, you can find various ways to help clean up the formula.

Notice how the "r/12" seems to show up a lot. Let's replace that fraction with the variable A.

So we'll make A = r/12

Because of that, the expression turns into

After replacing all the "r/12" terms with "A", we have the formula

turn into

which is a bit simpler in my opinion.

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We could also let

B = (1+A)^(12t)

which would then allow us to go from this

to this

and that's even more simple

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We're given the following values

P = 75,000 = amount loanedr = 0.023 = annual interest rate in decimal formt = 10 = number of years

Based on those values, we can say

A = r/12 = 0.023/12 = 0.00191667 approximatelyB = (1+A)^(12*t) = (1+0.00191667)^(12*10) = 1.25832348 approximately

From here, we plug the values of P, A, and B into the simplified version of the formula below.

The monthly payment is roughly $700.22