Mathematics: 100 POINT PLEASE HELP QUICK

100 POINT PLEASE HELP QUICK - id10013645755, gggghhhhhhhhhhhh

Ответ:

anthonylopez1

06.07.2021

$adjacent = \sqrt{ {50}^{2} - {14}^{2} } = 48 \\ \\ \sin(Q) = \frac{14}{50} = \frac{7}{25} \\ \cos(Q) = \frac{48}{50} = \frac{24}{25} \\ \tan(Q) = \frac{14}{48} = \frac{7}{24}$

$\sin(R) = \frac{48}{50} = \frac{24}{25} \\ \cos(R) = \frac{14}{50} = \frac{7}{25} \\ \tan(R) = \frac{48}{14} = \frac{24}{7}$

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Ответ:

leahumelinda

28.01.2022

Mathematics

lol this was a random question

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100 POINT PLEASE HELP QUICK

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