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16.09.2019 •
Mathematics
12 yellow balls and 14 red balls are placed in an urn. two balls are then drawn in succession without replacement. what is the probability that the first ball drawn is a red ball if the second ball drawn is yellow?
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Ответ:
Probability that the first ball drawn is a red ball if the second ball drawn is yellow = 7/13
Number of yellow balls, N(Y) = 12
Number of red balls, N(R) = 14
Total number of balls, N(Total) = 12 + 14
N(Total) = 26
Probability of picking a yellow a ball
Pr(Y) = N(Y) / N(Total)
Pr(Y) = 12/26 = 6/13
Probability of picking a red ball
Pr(R) = N(R) / N(Total)
Pr(R) = 14/26 = 7/13
Probability of the two balls are red and yellow
Pr(RnY) = 6/13 x 7/13
Pr(RnY) = 42/169
Probability that the first ball drawn is a red ball if the second ball drawn is yellow
Pr(R|Y) = Pr(RnY)/P(Y)
Pr(R|Y) = 42/169 ÷ 6/13
Pr(R|Y) = 42/169 x 13/6
Pr(R|Y) = 7/13
Probability that the first ball drawn is a red ball if the second ball drawn is yellow = 7/13
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Ответ:
12 + 14 = 26 balls total
probability of picking a red one first = 14/26 reduces to 7/13
then a yellow ball second would be 12/25
probability of both happening = 7/13 x 12/25 = 84/325
Ответ:
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