12h^2 kl+6hk=6hk (___+___)

f(-4) = 6

f(0) = -6

f(1) = -4

On a coordinate plane, a parabola opens up. It goes through (negative 4.25, 10), has a vertex of (negative 0.5, negative 6.2), and goes through (3.25, 10). Solid circles appear on the parabola at (negative 4, 6), (negative 2, negative 4), (negative 1, negative 6), (0, negative 8), (1, negative 4), (2, 0), and (3, 6).

Step-by-step explanation:

hope it helps