laylay120
17.08.2021 •
Mathematics
14. Determine the y-intercept of the quadratic function f(x) = x^2+ 8x - 13 please give detailed steps/walkthrough!! thank you
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Ответ:
When we talk about Intercept... We refer to the place where the line touches or Crosses a Mentioned axis.
In this question... We needed the y - Intercept
Know This: At the intercept of a mentioned axis...The other axis is zero at that point.
In other words... If we're asked for intercept at x-axis ... The y value at that point is zero and Vice Versa
So To find the y Intercept... the x value at this point is zero(0).
With this in Mind...
substitute x = 0 into the quadratic eqn
f(x) = 0² +8(0) - 13
f(x) = -13
This is Our Y Intercept .
To get the x intercept(if asked)
substitute y = 0 and solve
0 = x² + 8x - 13
This is a quadratic equation
Solving this would get you two value and those values would be your x intercept.
I hope it helps.
Have a great day.
Ответ:
The vertical acceleration when t = 325 s is -2.76 × 10⁻¹³² m/s²
Step-by-step explanation:
The relationship is given as follows;
Where:
y₀ = 0.75 m
α = 0.95 s⁻¹
ω = 6.3 s⁻¹
Given that the velocity, v, is found by the following relation;
The acceleration, a, can be found by differentiating the velocity with respect to time as follows;
Which gives;
Hence the vertical component of the acceleration is given as follows;
The vertical acceleration when t = 325 s = -2.76 × 10⁻¹³² m/s².