Mathematics: 15. center at (-2, 0), diameter 16 equation

15. center at (-2, 0), diameter 16 equation - id1520165915798, smortandsons

XTREME3336

23.01.2022

$(x+2)^{2}+y^{2}=64$

Step-by-step explanation:

The equation of a circle is given by $(x-h)^{2}+(y-k)^{2}=r^{2}$ , where (h,k) is the center and is the radius.

Substitute the points for and and simplify.

$(x-(-2))^{2}+(y-0)^{2}=r^2$

(x+2)^2 + y^2 =r^2

The diameter is given and the radius is half the length of the diameter, so the radius is 8

Substitute for

(x+2)^2 +y^2 =8^2

(x+2)^2 +y^2 =64

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geraldmorgan5580

13.02.2023

a. 10.4m above the cliff

b. 18.4m below the cliff

c. Os or 3.1s

d. 5.1s

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