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viktoria1198zz
01.12.2019 •
Mathematics
$190,258.50; $152,698.00; $122,753.00; $220,523.00; $231,951.00 find the average
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Ответ:
Average=Total sum divided by total quantity of numbers added.
190,258.50+152,698.00+122,753.00+220,523.00+231,951.00 = 918,183.50
918,183.50/5= 183,636.50
Hope this helps! :D
Ответ:
837,183.5 ÷ 5 = 167,436.7
Ответ:
x = 128.472
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The number of diners each day has a mean of 107 and a standard deviation of 60.
This means that![\mu = 107, \sigma = 60](/tpl/images/1391/3988/835f1.png)
Distribution of the daily average:
Over a month of 30 days, so![n = 30, s = \frac{60}{\sqrt{30}} = 10.955](/tpl/images/1391/3988/ebdcd.png)
The probability that a daily average over a given month is greater than x is 2.5%. Calculate x.
This is X when Z has a p-value of 1 - 0.025 = 0.975, so X when Z = 1.96. Then
By the Central Limit Theorem
So x = 128.472