Mathematics: -2(2p – 4) = 3(p + 12)

158.53 cmStep-by-step explanation:We know that the ends of a fishing line spool are circular in shape.Given : The area of an end of fishing line spool = (1)Area of a circle = (2)Circumference of a circle = (3), where r is radius of the circle.From (1) and (2), we have Circumference of fishing spool = (using (3))i.e. Fishing spool required to wind around the spool one time ⇒ Fishing spool required to wind around...

-2(2p – 4) = 3(p + 12) - id2243125713878, halimomohamed

Ответ:

baca23jasmine

22.01.2022

Mathematics

Step-by-step explanation:

so you try to get p on one side

-2(2p-4)=3(p+12)

-4p+8=3p+36

8=7p+36

-28=7p

-4=p

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Ответ:

afloareiandrei8615

13.09.2020

Mathematics

158.53 cm

Step-by-step explanation:

We know that the ends of a fishing line spool are circular in shape.

Given : The area of an end of fishing line spool = $20.0\cm^2$ (1)

Area of a circle = $\pi r^2$ (2)

Circumference of a circle = $2\pi r$ (3)

, where r is radius of the circle.

From (1) and (2), we have

$\pi r^2=20\\\\\Rightarrow\ r^2=\dfrac{20}{\pi}\\\\\Rightarrow\ r=\sqrt{\dfrac{20}{\pi}}$

Circumference of fishing spool = $2\pi r$ (using (3))

$=2\pi \sqrt{\dfrac{20}{\pi}}=2\sqrt{20\pi}=2\times2\sqrt{5\pi}=4\sqrt{5\pi}$

i.e. Fishing spool required to wind around the spool one time $=4\sqrt{5\pi}\ cm$

⇒ Fishing spool required to wind around the spool 10 times $=10\times4\sqrt{5\pi}\ cm=40\sqrt{5\pi}\\\\=40\times\sqrt{5}\times \pi\\\\=40\times2.236\times\sqrt{3.14159}\\\\=89.44\times1.772453\\\\=158.528205473\approx158.53\ cm$

Hence, you need 158.53 cm or about 159 cm of fishing line to wind around the spool 10 times.

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-2(2p – 4) = 3(p + 12)

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