adalan6986

09.12.2020 •

Mathematics

2. At the same time of day, a man who is 76 inches tall casts a 57-inch shadow, and his son casts a 24-inch shadow. What is the height of the man's son? (Figures may not be
drawn to scale.)
76 in.
57 in.
CL
-24 in.

2. At the same time of day, a man who is 76 inches tall casts a 57-inch shadow, and his

son casts

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Ответ:

sirdre1982

12.07.2022

Mathematics

$-2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})=-4.0551$

Step-by-step explanation:

Given : Expression $-2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})$

To find : Simplify the expression ?

Solution :

Using BODMAS,

$-2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})$

$=-\frac{44}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-\frac{45}{11})$

$=-\frac{44}{21}+(\frac{0.25}{14}+\frac{1.5\times 16}{3})\div(-\frac{45}{11})$

$=-\frac{44}{21}+(\frac{0.25}{14}+\frac{24}{3})\div(-\frac{45}{11})$

$=-\frac{44}{21}+(\frac{0.25\times 3+24\times 14}{14\times 3})\div(-\frac{45}{11})$

$=-\frac{44}{21}+(\frac{336.75}{42})\div(-\frac{45}{11})$

$=-\frac{44}{21}-\frac{336.75\times 11}{42\times 45}$

$=-\frac{44}{21}-\frac{3704.25}{1890}$

$=\frac{-44\times 1890-3704.25\times 21}{21\times 1890}$

$=\frac{-160949.25}{39690}$

=−4.0551

Therefore, $-2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})=-4.0551$

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2. At the same time of day, a man who is 76 inches tall casts a 57-inch shadow, and his son casts a 24-inch shadow. What is the height of the man's son? (Figures may not be drawn to scale.) 76 in. 57 in. CL -24 in.