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karenjunior
21.11.2019 •
Mathematics
(2 points) an article in the washington post on march 16, 1993 stated that nearly 45 percent of all americans have brown eyes. a random sample of n=76n=76 americans found 28 with brown eyes. we test h0: p=.45 ha: p≠.45
(a) what is the z-statistic for this test?
(b) what is the p-value of the test?
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Ответ:
a) z=1.43
b) 0.1528
Step-by-step explanation:
The given set of hypothesis :
Since the alternative hypothesis
is two-tailed , so we perform two-tailed test.
Also, it is given that : A random sample of n=76 Americans found 28 with brown eyes.
Sample proportion:![\hat{p}=\dfrac{28}{76}=0.3684](/tpl/images/0384/8153/cabf7.png)
a) The z-statistic would be :-
b) P-value for two-tailed test = 2P(Z>|z|)= 2P(z>|-1.43|)
=2P(z>1.43)
=2(1-P(z≤1.43)
=2-2P(z≤1.43)
= 2-2(0.9236)[Using standard z-table]
= 2-1.8472=0.1528
Hence, the P-value of the test= 0.1528
Ответ:
2000-5000 g
Step-by-step explanation:
Averagely, the weight of a new born baby is 7.5 lb, which is equal to 3.5 kg.
Converting this weight in kg to grams,
3.5 kg = 3.5 *1000 = 3500 g
From the answer choices, the value will range from 2000 g-5000 g