Mathematics: 2. solve 3^4x-5=(1/27) ^2x+10 for x. show your work.!

2. solve 3^4x-5=(1/27) ^2x+10 for x. show your - id2345127210314019, romanlittlewood

Ответ:

ciaralamont2

29.06.2019

$3^{4x-5}=\left(\dfrac{1}{27}\right)^{2x+10}\\\\3^{4x-5}=\left(\dfrac{1}{3^3}\right)^{2x+10}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\3^{4x-5}=\left(3^{-3}\right)^{2x+10}\qquad\text{use}\ (a^n)^m=a^{n\cdot m}\\\\3^{4x-5}=3^{-3(2x+10)}\qquad\text{use distributive property}\\\\3^{4x-5}=3^{(-3)(2x)+(-3)(10)}\\\\3^{4x-5}=3^{-6x-30}\iff4x-5=-6x-30\qquad\text{add 5 to both sides}\\\\4x=-6x-25\qquad\text{add 6x to both sides}\\\\10x=-25\qquad\text{divide both sides by 10}\\\\\boxed{x=-2.5}$

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Ответ:

badpotterchris

01.04.2023

Mathematics

the new standard deviation is greater than $27 is the answer

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2. solve 3^4x-5=(1/27) ^2x+10 for x. show your work.!

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