2. The mean birth weight of a full term boy born

Ответ:

pennygillbert

10.02.2022

Mathematics

The value is P( X < 7 ) =0.26226

The value is P( X < 7 ) = 0.00073

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 7.7 lbs$

The standard deviation is $\sigma = 1.1 \ lbs$

The sample size is n = 25

Generally the probability that a boy born full term in the US weighs less than 7 lbs is mathematically represented as

$P( X < 7 ) = P( \frac{X - \mu }{\sigma} < \frac{7 - 7.7 }{1.1 } )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

=> P( X < 7 ) = P(Z

From the z table the area under the normal curve to the left corresponding to -0.6364 is

P(Z

=> P( X < 7 ) =0.26226

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_{x} = \frac{ 1.1 }{\sqrt{25} }$

=> $\sigma_{x} = 0.22$

Generally the probability that the average weight of 25 baby boys born in a particular hospital have an average weight less than 7 lbs is mathematically represented as

$P( \= X < 7 ) = P( \frac{\= X - \mu }{\sigma_{x}} < \frac{7 - 7.7 }{ 0.22 } )$

=> P( X < 7 ) = P(Z

From the z table the area under the normal curve to the left corresponding to -3.1818 is

=> P(Z

=> P( X < 7 ) = 0.00073

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