2) USE THE UNIT CIRCLE TO FIND THE VALUES OF THE SIX TRIGONOMETRIC
FUNCTIONS FOR A 150° ANGLE

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Ответ:

diego481

02.06.2022

Mathematics

$\tan \theta = \boxed {2} \sqrt{\boxed{6}}$

Step-by-step explanation:

$\sec \theta = 5 \: \: (given) \\ \because \: \tan^{2} \theta = { \sec}^{2} \theta - 1\\ \therefore \: \tan \theta = \pm \sqrt{{ \sec}^{2} \theta - 1} \\ = \pm \sqrt{{5}^{2} - 1} \\ = \pm \sqrt{25 - 1} \\ = \pm \sqrt{24} \\ \therefore \: \tan \theta = \pm 2\sqrt{6} \\ \because \theta \: lies \: in \: the \: first \: quadrant \\ \ \therefore \: \tan \theta = \boxed {2} \sqrt{\boxed{6}}$

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2) USE THE UNIT CIRCLE TO FIND THE VALUES OF THE SIX TRIGONOMETRIC FUNCTIONS FOR A 150° ANGLE