(20pts=5pts each) For parts (a)–(d) answer the questions and complete the statements in the space provided: line EC ∩ line AC ∩ line BC = C , m∠ECA=32°, m∠CEF=150°

Step-by-step explanation:

Since you didn't state what you're looking for, I will lost out all the angles in the picture instead.

Given that

∠CEF = 150°

∠ECA = 32°

∠CEA = 180 - ∠CEF(angles in a straight line)

∠CEA = 180 - 150

∠CEA = 30°

∠EAC = 180 - ∠CEA - ∠ECA(angles in a triangle)

∠EAC = 180 - 30 - 32

∠EAC = 118°

∠CAB = 180 - ∠EAC(angles in a triangle)

∠CAB = 180 - 118

∠CAB = 62°

∠ACB = ∠CEA = 30°(similar angles)

∠ABC = 180 - ∠CAB - ∠ACB(angles in a triangle)

∠ABC = 180 - 62 - 30

∠ABC = 88°

∠ECB = ∠ECA + ∠ACB(angles in a triangle)

∠ECB = 32 + 30

∠ECB = 62°

∠CEA + ∠ECB + ∠ABC = 180

30 + 62 + 88 = 180°.

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