24. Rectangle JKLM with vertices J(6, 12), K(15, 12), L(15, -8), and M(6, -3): k = 1/3
S
“
3
J” ( 1 -
K' ( -
L” (
M (
LLLL
511

Line EG equals 12

Step-by-step explanation: The first clue given here is the fact that line EF is the midpoint of line EG. Line EF measures 6x while line EG measures 13x. Being the midpoint of the line EG, EF times 2 would be equal to EG. Alternatively EG divided by 2 would be equal to EF. Hence,

6x (2) = 13x

By cross multiplication we now have

2 = 13x/6x

2 = (13/6) x

By cross multiplying yet againz we now arrive at

(2 x 6)/13 = x

12/13 = x

If EG has been given as 13x, and x has been derived as 12/13, then

EG = 13x

EG = 13(12/13)

EG = 12