:25 points! jeremy constructed this solid by combining two rectangular prisms and a square pyramid. what is the surface area of this figure?

Triangle area:
 A1 = (1/2) * (6) * (7)
 A1 = 21
 Rectangle area of the base:
 A2 = (14) * (6)
 A2 = 84
 Area of the posterior rectangle:
 A3 = (5) * (6)
 A3 = 30
 Area of the frontal rectangle:
 A4 = (6) * (2)
 A4 = 12
 Area of the rectangle parallel to the base:
 A5 = (8) * (6)
 A5 = 48
 Rectangle area located between posterior and front rectangles:
 A6 = (3) * (6)
 A6 = 18
 Area of the side walls of the figure:
 A7 = (14) * (2) + (3) * (6)
 A7 = 28 + 18
 A7 = 46
 Superficial area:
 A = 4 * A1 + A2 + A3 + A4 + A5 + A6 + 2 * A7
 A = 4 * 21 + 84 + 30 + 12 + 48 + 18 + 2 * 46
 A = 368
 
 A = 368 m ^ 2

here's the steps

Step-by-step explanation:

first, you need to get x by itself.In order to do that you need to do the opposite to the other side. ex: x5= 1/10; what you would do is divide 1/10 by 5 to get x = 0.5 , 5/10