Mathematics: 2log4 + 3log2 express as a single logarithm

2log4 + 3log2 express as a single logarithm - id2432350159, marie0321rivera67

Ответ:

yurrrkassi

10.03.2022

$\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ log_a(xy)\implies log_a(x)+log_a(y)\qquad \qquad \end{array} \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ log_a\left( x^b \right)\implies b\cdot log_a(x) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 2log(4)+3log(2)\implies log(4^2)+log(2^3) \implies log(4^2\cdot 2^3)\implies log(128)$

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Ответ:

jennywarmJones

24.08.2020

Mathematics

x=±

Step-by-step explanation:

We want to solve the equation

We first have to assume that since the value is not defined for .

Now, since divides the right hand side of the equation, we multiply the two sides of this equation by to get that

Hence, by dividing the equation by it follows that

and so

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2log4 + 3log2 express as a single logarithm

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