( 2x^4+2x^3+x^2-x-1 ) \ ( x^2-x-1 )

Ответ:

jay8682

21.01.2022

$\frac{2 {x}^{4} + 2 {x}^{3} + 2 {x}^{2} + 2 {x}^{2} - x - 1 }{ {x}^{2} - x - 1 } = 2 {x}^{2} + 4x + 8 + \frac{11x + 7}{ {x}^{2} - x - 1 }$

Step-by-step explanation:

We want perform the following polynomial division.

$\frac{2 {x}^{4} + 2 {x}^{3} + 2 {x}^{2} + 2 {x}^{2} - x - 1 }{ {x}^{2} - x - 1 }$

We carry out the polynomial division in the attachment to obtain:

$\frac{2 {x}^{4} + 2 {x}^{3} + 2 {x}^{2} + 2 {x}^{2} - x - 1 }{ {x}^{2} - x - 1 } = 2 {x}^{2} + 4x + 8 + \frac{11x + 7}{ {x}^{2} - x - 1 }$

See attachment;

$( 2x^4+2x^3+x^2-x-1 ) \ ( x^2-x-1 )$

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jeffffffff

01.04.2023

x=3/5

Step-by-step explanation:

-3(4x-7)=15-2x

-12x+21=15-2x

-12x+2x=15-21

-10x=-6

x=3/5

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