2x - 4y = 10 2y+6=x

What is the best method to solve this system?

Equal values
Substitution
Elimination

What is the solution to the system?

someone please help asap

Substitution, but this system of equations has no solution.

Step-by-step explanation:

2x-4y=10

2y+6=x

2(2y+6)-4y=10

4y+12-4y=10

12=10

no solution.

Step-by-step explanation:

Given:

(y/y - 4) - (4/y + 4) = 32/y^2 - 16

Note y^2 - 16 = (y - 4 ) × (y + 4)

Multiplying the equation; both sides by y^2 - 16,

y (y + 4) - (4(y - 4)) = 32

y^2 + 4y - 4y + 16 = 32

y^2 = 32 - 16

Squaring both sides,

y = sqrt(16)

= 4