2x − 5y = 3
x − 3y = 1
(4, 1)
(5, 2)
(7, 2)
(9, 3)

Assuming this a system of equations and you need the solution set, you can solve it by elimination or substitution--whichever you find easier. i'll use elimination:

2x - 5y = 3
x - 3y = 1

here, it'll be pretty easy to get your x values to match so you can cancel them out. just multiply your bottom equation by 2, then subtract:

   2x - 5y = 3
- (2x - 6y = 2)
your 2x's cancel out and -5y + 6y is simply y, so you're left with:

y = 1

that already gives you your answer, because you can see that the first ordered pair is the only pair with a y-value that's 1, but still, to check your x-value, you just plug your y-value into one of the equations:

x - 3(1) = 1
x - 3 = 1
x = 4

so your solution is (4, 1).

Solution given:

A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm

and

base[b]PR=60cm.

perpendicular [P]= QR

by using Pythagoras law

h²=p²+b²

80²=QR²+60²

QR²=80²-60²

QR=

QR=20=52.9=53cm

QR=53cm.