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rebecca7415
27.11.2020 •
Mathematics
3
2
Show gred
1
16
-5
4
1 2
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5 6
3 -2 -1
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- x2. on
sin - cos - tan-
+ - X + / +
log-e? 10
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10n
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Ответ:
The gradient of the graph below is![\mathbf{\frac{3}{2} }](/tpl/images/0930/5411/361dc.png)
Step-by-step explanation:
We need to calculate the gradient of the graph
The gradient of graph is actually slope of the graph.
The slope of graph can be calculated using formula:![Slope=\frac{y_2-y_1}{x_2-x_1}](/tpl/images/0930/5411/3d683.png)
Taking any 2 points on graph i.e
(1,0) and (-1,-3)
We have![x_1=1, y_1=0, x_2=-1,y_2=-3](/tpl/images/0930/5411/5688b.png)
Putting values and finding gradient:
So, The gradient of the graph below is![\mathbf{\frac{3}{2} }](/tpl/images/0930/5411/361dc.png)
Ответ:
Option 1. (-1, 1 ) is the correct option.
Step-by-step explanation:
The given polynomial function is
To find the real zeros of any polynomial we follow the procedure as below
First we find p/q where p represents the factors of constant term of the polynomial and q represents the factors of the coefficient of highest degree term of the expression.
So factors will be = p/q = ± factors of 2/ ± factors of 2
= ±1, ±2/±1, ±2
So the probable factors are ±1, ±2
Now by putting the values of x in the polynomial![f(x) = 2x^{4}-x^{3}+x-2](/tpl/images/0368/3582/5c222.png)
For x = 1
f(x) = 2 - 1 + 1 - 2 = 0
Therefore (x-1) is a factor.
For x = -2
f(x) = 2×16 + 8 -2 -2 = 36
So its not the factor.
For x = -1
f(x) = 2 + 1 - 1 - 2 = 0
Therefore for x = -1 and x= 1 f(x) is zero.