3(3x-3) ≥ -9x + 5 what are the solutions of the inequality?

First, distribute -3 into (3x-3). This would equal -9x+9. Your new equation would be:

-9x+9≥-9x+4

There cannot be the same variable on both sides of the equation, so add 9x to each side.

9≥4

Because 9 is greater than or equal to 4, x can be any number at all.

X is equal to all real numbers

20

Step-by-step explanation: