3. a circle is given by the equation x^2+y^2=100. which of the following points are on the circle?
a. (0,10)
b. (−8,6)
c. (−10,−10)
d. (45,55)
e. (−10,0)

Options A, B and E

Step-by-step explanation:

To the breakdown:

For a point to be on the circle it must satisfy the equation of a circle.

From the question we are given the equation of the circle as:

x^2 + y^2 = 100;

To determine the points that can be present in the circle we check each point against the equation and see if the Left hand (LHS)and Right hand (RHS)side of the equation are equal. So lets start:

a) (0,10) => x = 0, y = 10;

(0)^2 + (10)^2 = 100; so the LHS and RHS of the equation are the same.

b) (-8, 6) => x= -8, y = 6;

(-8)^2 + (6)^2 = 64 + 36 = 100; so the LHS and RHS are equal.

c) (-10, -10) => x=-10, y=-10;

(-10)^2 + (-10)^2 = 100+100= 200; the LHS is greater than the RHS.

d) (45, 55) => x=45, y=55;

(45)^2 + (55)^2 = 2025 + 3025 = 5050; the LHS is greater than the RHS.

e) (-10, 0) => x=-10, y= 0;

(-10)^2 + (0)^2 = 100; so the LHS and the RHS are equal.        

The answer would be B. 1 because by using the pythagorean theorem ((a^2)+(b^2)=(c^2)) on this right triangle, (a^2)=((sqrt(3))^2)=3, (b^2)=?(let's use x), and (c^2)=(2^2)=4. So, (c^2)-(a^2)=(b^2). 4-3=1 and (sqrt(1))=1.