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gleatons429
13.11.2020 •
Mathematics
30/90 del número de plantas en un cultivo de caña está contaminada. De estas, el 1/2 ha sido tratada. ¿Cual es la fracción del número de plantas del cultivo que no ha sido tratada?
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Ответ:
Usando proporciones, se encuentra que la fracción del número de plantas del cultivo que no ha sido tratada es![\mathbf{\frac{5}{6}}](/tpl/images/0896/2738/e9247.png)
Las plantas que no han sido tratadas son:
Las que non estan contamidas(6/9 de el total).1/2 de las contaminadas(1/2 de 3/9).Por eso, la proporción total es dada por:
La fracción del número de plantas del cultivo que no ha sido tratada es![\mathbf{\frac{5}{6}}](/tpl/images/0896/2738/e9247.png)
Un problema similar es dado en link
Ответ:
1/6
Step-by-step explanation:
De la pregunta, sabemos:
30/90 del número de plantas de un cultivo de caña está contaminado.
30/90, simplificamos aún más
30/90 => 3/9 => 1/3
De estos, la mitad han sido tratados.
La fracción de los cultivos tratados son:
1/2 de 3/9 = 1/2 × 1/3
= 1/6
La fracción del número de plantas del cultivo que no ha sido tratada se calcula como:
1/3 - 1/6
El mínimo común denominador es 6
= (2 × 1) - (1 × 1) / 6
= 2 - 1/6
= 1/6
Ответ:
5.25
Step-by-step explanation:
The fact that the graph crosses the x-axis means the hyperbola opens to the left and right. Hence its equation is ...
x^2/a - y^2/b = 1
The point (-2, 0) helps us find "a":
(-2)^2/a - 0/b = 1
4 = a
Then we can find "b" from the other fully-specified point.
(-3)^2/4 - 4^2/b = 1 . . . . . . substitute (-3, 4) for (x, y)
b = 16/(9/4 -1) = 64/5 . . . . solve for b
Then the third point will satisfy ...
t^2/4 - (5/64)·2^2 = 1 . . . . . . substitute (t, 2) for (x, y)
t^2 = 4·(1 +5/16) = 4 +5/4 . . . . solve for t^2
t^2 = 5.25