30 points! answer and show work for both! (5x−1)/7 + (4x−3)/2 − (3−2x)/2 = 6 (4x−3)/2 − (5−2x)/3 − (3x−4)/3 = 5

The recommended approach for such equations is to eliminate fractions first, by multiplying by the LCM of the denominators. You can simply simplify, then work them as a 2-step linear equation, doing your arithmetic with the fractions as they are.

a) (5x-1)/7 + (4x-3)/2 -(3-2x)/2 = 6 . . . . . given

... 2(5x -1) +7(4x -3) -7(3 -2x) = 84 . . . . . multiply by 14

... 10x -2 +28x -21 -21 +14x = 84 . . . . . . eliminate parentheses

... 52x -44 = 84 . . . . . . . . . . . . . . . . . . . . collect terms

... 52x = 128 . . . . . . . . . . . . . . . . . . . . . . . add 44

... x = 32/13 . . . . . . . . . . . . . . . . . . . . . . . . divide by 52 and simplify

b) (4x−3)/2 − (5−2x)/3 − (3x−4)/3 = 5 . . . given

... 2x -3/2 -5/3 +(2/3)x -x +4/3 = 5 . . . . . . .eliminate parentheses

... (5/3)x -11/6 = 5 . . . . . . . . . . . . . . . . . . . . simplify

... (5/3)x = 41/6 . . . . . . . . . . . . . . . . . . . . . . add 11/6

... x = (41/6)/(5/3) = 41/10 . . . . . . . . . . . . . .divide by the coefficient of x

Using the first method, you're dealing with integers and you can do a lot of the math in your head. Using the second method, you're dealing with fractions and mixed numbers. A calculator can be helpful, especially if it handles arithmetic with fractions nicely, as many graphing calculators do.

Step-by-step explanation:

Please help me ASAP!

50 Points for Correct answer!!

Quadrilateral WXYZ is on a coordinate plane.

Segment XY is on the line x - y = -3, and segment WZ is on the line x - y = 1. Which statement proves how segments XY and WZ are related?

A: They have slopes that are opposite reciprocals of 1 and -1 and are, therefore, perpendicular.

B: They have the same slope of 1 and are, therefore, parallel.

C: They have slopes that are opposite reciprocals of 0 and undefined and are, therefore, perpendicular.

D: They have the same slope of -1 and are, therefore, parallel.

x-y = -3  => y = x+3...........(1)  => slope = coefficient of x = 1

x-y = 1  => y = x-1 ..............(2) => slope = coefficient of x = 1

Therefore the correct statement is

They have the same slope of 1 and are, therefore, parallel.

(see also graph, attached)