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hardwick744
09.04.2020 •
Mathematics
– 4/9 (18 – 17) is equivalent to which value?
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Ответ:
Given:
Model tile length =![\dfrac{1}{3}\text{ in.}](/tpl/images/0840/3436/32598.png)
Model tile width =![\dfrac{1}{4}\text{ in.}](/tpl/images/0840/3436/a6b5c.png)
Actual tile length =![\dfrac{1}{4}\text{ ft.}](/tpl/images/0840/3436/0bca2.png)
Actual tile width =![\dfrac{3}{16}\text{ ft.}](/tpl/images/0840/3436/a2bb0.png)
To find:
The ratio of the length of a tile in the model to the length of an actual tile and the ratio of the area of a tile the model to the area of an actual tile.
Solution:
We know that,
1 ft = 12 in.
Actual tile length![=\dfrac{1}{4}\times 12\text{ in.}](/tpl/images/0840/3436/322f1.png)
Actual tile width![=\dfrac{3}{16}\times 12\text{ in.}](/tpl/images/0840/3436/34500.png)
The ratio of the length of a tile in the model to the length of an actual tile is
Therefore, the ratio of the length of a tile in the model to the length of an actual tile is
or it can be written as 1:9.
Area of rectangle = length × width
Area of model tile![=\dfrac{1}{3}\times \dfrac{1}{4}](/tpl/images/0840/3436/e6f3b.png)
Area of actual tile![=3\times \dfrac{9}{4}](/tpl/images/0840/3436/28cd0.png)
The ratio of the area of a tile the model to the area of an actual tile is
Therefore, ratio of the area of a tile the model to the area of an actual tile is
or it can be written as 1:81.