4. a stack of playing cards contains 4 jacks, 5 queens, 3 kings, and 3 aces. two cards will be randomly selected from the stack. what is the probability that a queen is chosen and replaced, and then a queen is chosen again?

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➷ 5 + 3 + 3 + 4 = 15

5/15 * 5/15 = 25/225

This can be simplified to 1/9

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➶ Hope This Helps You!

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Total cards = 4 + 5 + 3 + 3 = 15 cards.

There are 5 queens, picking 1 queen would equal 5/15 which reduces to 1/3.

Because the queen is replaced and then you pick again, the probability would be the same as the first time. 1/3.

To find the overall probability of picking 2 queens, multiply each probability together: 1/3 x 1/3 = 1/9 total probability.

It helps thinking of Sin, Cos, Tan as SOH-CAH -TOA. SOH meaning Sin= Opposite/ Hypotenuse, CAH meaning Cos= Adjacent/ Hypotenuse and TOA meaning Tan= Opposite/ Adjacent. Anything across from the Reference point is Opposite, what is across from Opposite is adjacent and what is across from the right angle is Hypotenuse. I hope I’m answering your question correctly and hope this helps!