Mathematics: 4. Determine the magnitude and direction of the vector v = 5, -6 . f. 11, NE g. 61, SE h. 111, NE j. V61, SE

answer: 15 x 34/ 16 = 31 hoped this...

4. Determine the magnitude and direction of the

DisneyGirl11

14.02.2022

The magnitude of vector is:

$\left|\begin{pmatrix}5&-6\end{pmatrix}\right|=\sqrt{61}$

v = <5, -6> means the vector has x-coordinate x = 5 and y-coordinate y = -6, so the vector v = <5, -6> is heading towards SE.

Thus, option ( j ) is correct.

i.e. $\sqrt{61},\:SE$

Step-by-step explanation:

Given the vector

v = <5, -6>

Determining the magnitude of the vector

To find a magnitude of a vector v = (a, b) we use the formula

$||v||\:=\:\sqrt{a^2+b^2}$

Magnitude of the vector is basically termed as the length of the vector, which is denoted by

$|\left(5,\:-6\right)|=\sqrt{\left(5\right)^2+\left(-6\right)^2}$

$=\sqrt{5^2+6^2}$

$=\sqrt{25+36}$

$=\sqrt{61}$

Thus, the magnitude of vector is:

$\left|\begin{pmatrix}5&-6\end{pmatrix}\right|=\sqrt{61}$

As the vector v = <5, -6> lies in 4th quadrant.

v = <5, -6> means the vector has x-coordinate x = 5 and y-coordinate y = -6, so the vector v = <5, -6> is heading towards SE.

Thus, option ( j ) is correct.

i.e. $\sqrt{61},\:SE$

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