4 of 204 of 20 Questions Question 4
What is the equation of the line that is parallel to y−5=−13(x+2) and passes through the point (6,−1)?

y= -13x+77

Step-by-step explanation:

Parallel lines do not share any points but have the same slope.

First, put the equation y-5=-13(x+2) into slope-intercept form.

y= -13x-21

Slope= -13x

Y-Intercept= (0,-21)

Now that we know the slope...

y-(-1)=-13(x-6)

becomes

y+1=-13x+78

y-1=-13x+78-1

y=-13x+77

5 miles

Step-by-step explanation:

We are given that A varsity cross-country team runs on a course that makes a right turn after 3 miles, and continues on one mile less than the junior varsity team's course.

The junior varsity team's course runs on a straight line from the same starting point and the finish line.

Refer the attached figure

Let the junior runs course x miles i.e. AC = x

Senior runs 3 miles i.e. BC = 3 miles

Senior  continues on one mile less than the junior ie. AB = x-1

Since ΔABC is a right angles triangle

So,

Thus the junior varsity team's course is 5 miles long.