4g over 16 minus 3 over 8 minus g over 16 equals 3 over 16

4g/16 - 3/8 - g/16 = 3/16

Add 3/8 to each side of the equation

4g/16 - g/16 = 3/16 + 3/8

Get a common denominator of 16 on the right side of the equation to add 3/8 to 3/16. To do this multiply the top and bottom of 3/8 by 2

4g/16 - g/16 = 3/16 + 6/16

Combine like terms. (Add the 4g/16 and g/16 together, and add 3/16 and 6/16 together).

3g/16 = 9/16

Now cross multiply. To do this, multiply the denominator of the first fraction (16) by the numerator of the second fraction (9), and set this equal to the numerator of the first fraction (3g) multiplied by the denominator of the second fraction (16).

16(9) = 3g(16)

144 = 48g

Now divide each side of the equation by 48.

g = 3

Hope this helps!

Given:

In ΔOPQ, m∠Q=90°, m∠O=26°, and QO = 4.9 feet.

To find:

The measure of side PQ.

Solution:

In ΔOPQ,

       [Angle sum property]

According to Law of Sines, we get

Using the Law of Sines, we get

Substituting the given values, we get

Approximate the value to the nearest tenth of a foot.

Therefore, the length of PQ is 2.4 ft.