5.2-3 In a satellite radio system, 500 stations of stereo quality are to be multiplexed in one data stream. For each station, two (left and right) signal channels each of bandwidth 15, 000 Hz are sampled, quantized, and binary-coded into PCM signals. (a) If the maximum acceptable quantization error in sample amplitudes is 1% of the peak signal voltage, find the minimum number of bits needed for a uniform quantizer.

the minimum number of bits needed for quantization is 7

Step-by-step explanation:

Given the data in the question;

if quantization is Δv, then the maximum quantization Error is Δv/2

now if we split up the whole range  from - to evenly into L levels, so

Δv = / L

Δv / 2 = / L

given that the error must be at most 1% of ,

1% = / L

1/100 × = / L

100 = L

now L must be a factor of 2 to be binary encoded,

so lets consider;

L = 128

2ⁿ = 128¹

2ⁿ = 2⁷

n = 7

Therefore, the minimum number of bits needed for quantization is 7

Russell is correct.

Step-by-step explanation:

It is given that Quadrilateral PQRS is located at P (0, 1), Q (3, 2), R (4, 0), and S (1, −1).

Distance formula:

Slope formula:

Using distance and slope formula find the length and slope of each side.

Segment PQ : P(0, 1) and Q(3, 2).

Segment SR : S(1, −1) and R(4, 0).

Segment PS : P(0, 1) and S (1, −1)

Segment QR : Q(3, 2) and R(4, 0)

Slope of parallel lines are same.

Segments PQ and SR are both congruent and parallel, and segments PS and QR are both congruent and parallel.

PQRS is a parallelogram because opposite sides are both congruent and parallel.

Product of slopes of perpendicular lines is -1.

Product of slope of two adjacent sides is

Therefore adjacent sides are not perpendicular. It means the PQRS is not a rectangle.

Therefore, Russell is correct.