5. a rectangular pool ha a length that is 13 meters longer than its width. perimeter is74 meters. what is the width its of this pool?

Good evening Brian,

For this problem, let's look at what we're given.  So we have a pool with a length that is 13 m (meters) longer than its width, and we're given the perimeter, or distance around the entire pool, which is 74 m.

We know that the pool has a rectangular shape and that the perimeter of a rectangle is width + length + width + length ⇒ 2(W) + 2(L).

Given the information provided, we can rewrite the equation to fit this problem.  Since we're told that the length is equal to 13 m + the width, so we can represent the length as W +13 m.  We can now rewrite the perimeter equation to be:

2(w) + 2 (w + 13 m) ⇒ 2(w) + 2(w) + 2(13 m) ⇒ 4(w) + 26 m = 74 m.

We're down to one variable now so this should be easy.  Subtract 26 m from both sides,

4(w) = 48 m

Now divide each side by 4 in order to find the width.

w = 12 m

-Hope this helps!

The odds would be 1/15.

To find these odds, you first have to find the total number of cards.

2 + 3 + 1 + 4 = 10 cards

Then you can find the first set of odd for pulling a green card by placing the goal amount over the total amount.

3 green / 10 total = 3/10

Now, with that green card not being replaced, we have one less green and one less total. This gives us 2 green and 9 total, which helps us find the odds of pulling one again.

2 green / 9 total = 2/9

Now to find the odds of doing both, you need to multiply the two odds together.

3/10 * 2/9 = 6/90 or simplified 1/15