lizzie3545
09.10.2019 •
Mathematics
5. during the eruption of mount st. helens in 1980. debris was ejected at a speed of over 440 feet per second
(300 miles per hour). the elevation in feet above sea level of a rock ejected at an angle of 75° above
horizontal is given by the function y(1) --1612 +425t+8200 where t is the time in seconds after the
iption. the rock's horizontal distance in feet from the point of ejection is given by x(i) = 1131. if the rock
landed at an elevation of 6000 feet, what is the horizontal distance from the point of ejection to where it!
landed rounded to the nearest hundred feet?
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Ответ:
3500 ft
Step-by-step explanation:
We assume you intend the equations to be ...
Then we can solve the second equation for t and use that in the first equation. We can solve the first equation for y=6000.
x = 113t
t = x/113
y(t) = y(x/113) = -16(x/113)² +425(x/113) +8200 = 6000
(16/12769)x² -(425/113)x -2200 = 0 . . . . . . subtract 6000, multiply by -1
Using the quadratic formula, the positive solution is ...
x = ((425/113) +√((-425/113)² -4(16/12769)(-2200))/(2(16/12769))
The fraction in the denominator can be inverted and used as a multiplier. We also use a√b = √(a²b) to simplify the radical.
x = (48025 +√4104275825)/32
x ≈ 3502.8
Rock was thrown about 3500 feet horizontally.
Ответ:
7 kittens
Step-by-step explanation:
5 · y = 4 · 35
5y = 140
5y ÷ 5 = 140 ÷ 5
y = 28
35 - 28 = 7