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alex8366
16.11.2020 •
Mathematics
5) It is known that ∠BAM and ∠CTX are complementary. If m∠BAM = x + 2 4 and m∠CTX = x + 11, then solve for the value of x algebraically.
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Ответ:
x =![27.5^{o}](/tpl/images/0900/8868/4c055.png)
Step-by-step explanation:
complementary angles are two or more angles whose sum is equal to
.
Thus given that;
m<BAM = x + 24
m<CTX = x + 11
So that,
m<BAM + m<CTX = 90
⇒ (x + 24) + (x + 11) = 90
x + 24 + x + 11 = 90
2x + 35 = 90
2x = 90 - 35
2x = 55
x =![\frac{55}{2}](/tpl/images/0900/8868/8a97d.png)
= 27.5
The value of x is
.
So that,
m<BAM = x + 24
= 27.5 +24
=![51.5^{o}](/tpl/images/0900/8868/cc112.png)
m<CTX = x + 11
= 27.5 + 11
=![38.5^{o}](/tpl/images/0900/8868/3ffc4.png)
Ответ:
B
Step-by-step explanation:
cos =adjacent divided by hypotenusecos A= 10÷26 =0.3846