5. The graph of a function is a line that passes through the coordinates (2, 11)
and (8, 14).
Write an equation in the form
y = mx + b for this function.

y = 1/2x + 10

Step-by-step explanation:

(y-11)/(14-11) = (x-2)/(8-2)

(y-11)/3 = (x-2)/6

2y-22 = x-2

2y = x + 20

y = 1/2x + 10

Let m = slope of the line.

m = (14 - 11)/(8 - 2)

m = 3/6

m = 1/2

We now have the slope and the slope is 1/2.

We plug the slope and one of the point into the point-slope formula.

Here is the point-slope formula:

y - y_1 = m(x - x/_1)

I will use the point (2, 11).

y - 11 = (1/2)(x - 2)

y - 11 = (1/2)x - 1

Now we solve for y by adding 11 to both sides of the equation.

y = (1/2)x - 1 + 11

y = (1/2)x + 10

A) 0.5(2) + 80 = 81

B) 83

C) f(4) = 0.5(4) + 80 = 82

g(x) = 2x + 79

Slope: (83-81)/(2-1) = 2

y = 2x + c

When x = 1, y = 81

81 = 2 + c

c = 79

g(x) = 2x + 79

g(4) = 2(4) + 79 = 87

Since 87 > 82,

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