5 times the sum of the digits of a two digit number is 9 less than the number formed by reversing its digits. If 4 times the value of the digit at ones place is equal to the half of the place value of the digit at tens place, find out the number.

5 times the sum of the digits of the number is 9 less than the number formed by reversing digits. → x = (5y - 9)/4 -- equation (1). Case - 2 : And, 4 times the value of the digits at ones place is equal to half the place value of digit at tens place (10x/2).

Step-by-step explanation:

If x is the number of hours, then:

48 = 10x + 7

41 = 10x

x = 4.1