Kadancepiggott7
20.04.2021 •
Mathematics
50 Pts cxxxxxxxxxcxbb
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Ответ:
mnnn
just for points i need
Ответ:
sorry po d ko po alam yan eh
Ответ:
The Answer is: i, where "i" is an imaginary number, the square root of negative 1.
Step-by-step explanation:
(2x^2 + 2x + 3) - (x^2 + 2x + 1) =
2x^2 + 2x + 3 - x^2 - 2x - 1 =
2x^2 + 2 =
2x^2 = -2
x^2 = -2/2
x^2 = -1
x = Sqrt -1 = i, where "i" is an imaginary number, the square root of negative 1.