Mathematics: 6-1. let x have a poisson distribution with a mean of 4. find (a) p(2≤x≤5). (b) p(x≥3). (c) p(x≤3).

6-1. let x have a poisson distribution with a mean

Ответ:

asdfghhk9805

12.03.2022

The mean of a Poisson distribution coincides with its rate parameter, so $\lambda=4$ . We have a PMF of

$f_X(x)=\dfrac{e^{-4}4^x}{x!}$

So,

a. $\mathbb P(2\le X\le5)=\dfrac{e^{-4}4^2}{2!}+\cdots+\dfrac{e^{-4}4^5}{5!}\approx0.6936$

b. $\mathbb P(X\ge3)=\dfrac{e^{-4}4^3}{3!}+\dfrac{e^{-4}4^4}{4!}+\cdots\approx0.7619$

c. $\mathbb P(X\le3)=\dfrac{e^{-4}4^0}{0!}+\cdots+\dfrac{e^{-4}4^3}{3!}\approx0.4335$

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Ответ:

rachelbrooks764

02.02.2021

Mathematics

$102,153.13

Explanation:

Amount payable on December 31 each of the next two years = $56,500

The PV of ordinary annuity of ($1,7%,2 years) is 1.80802

The amount of the notes receivable net of the unamortized discount = Amount Payable * PV($1, 7%, 2)

= $56,500 * 1.80802

= $102,153.13

So, the amount of the notes receivable net of the unamortized discount on December 31, 2020 will be $102,153.13.

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6-1. let x have a poisson distribution with a mean of 4. find (a) p(2≤x≤5). (b) p(x≥3). (c) p(x≤3).

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