6. Henry examined the table that represents values satisfying the function shown below.
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0 -18
1
2
4.
3
4.
-6
5 -8
6 0
7 24
8 70
Ollo
Based on the information in the table, select all the key features that are correct.
The y-intercept of the graph of the function is at (0, -18)
The maximum value of the function is 4.
A local minimum is located within the interval 3 sxs6
A local maximum is located within the interval 1 The function is increasing within the interval 6 sxs8
n

The maximum value of the function is 4

Step-by-step explanation:

Part A: Linear function

Part B: Y = -1000×X + 19463

Y = -1076.7×X + 19602

Part C: There will be significant difference, car 1 will be worth 628  more than car 2 after 10 years

Step-by-step explanation:

The table for the value of the two cars with time are given as follows;

Years                               Car 1                                     Car 2                

1                                     18,500                                    18,500

2                                    17,390                                     17,500

3                                    16,500                                     16,346.6

Plotting the give data, we have;

From the plot of the data, the function that can be used to describe the values of both cars after a fixed number of years is a linear function

Part B

From the relation for linear regression formula, Y = b·X + a, we have ;

For car 1

ΣXY = 102780

(ΣX)² = 36

ΣX = 6

ΣY = 52390

ΣX² = 14

N  = 3

b = -1000

a = 19463

Y = -1000×X + 19463

For Car 2

ΣXY = 102539.8

(ΣX)² = 36

ΣX = 6

ΣY = 52346.6

ΣX² = 14

N = 3 .

b = -1076.7

a = 19602

Y = -1076.7×X + 19602

Part C:

For Car 1 after 10 years, we have;

Y = -1000×X + 19463

Y = -1000×10 + 19463 = 9,463

For Car 2 after 10 years, we have;

Y = -1076.7×X + 19602

Y = -1076.7×10 + 19602 = 8,835

Therefore, car 1 will be worth 9,463 and car 2 will be worth 8,835 therefore, car 1 will be worth (9,463 - 8,835) = 628  more than car 2 after 10 years.