Mathematics: (60 points to best answer) (asap and you) kayla wants to find the distance, ab, across a creek. she starts at point b and walks along the edge of the river 62 ft and marks point c. then she walks 93 ft further and marks point d. she turns 90° and walks until her final location and marks point e. point e, point a, and point c are collinear. can kayla conclude that ∆abc and ∆edc are similar? why or why not? suppose (de) ̅=125 ft. calculate the distance of (ab) ̅ to the nearest tenth of a foot. show

Yes because it starts from the origin and is a straight lineStep-by-step explanation:...

(60 points to best answer) (asap and you) kayla wants

kcarstensen59070

15.01.2022

$83.\overline{3}\text{ feet}$

Step-by-step explanation:

Since, In the given diagram,

The sides of the triangles ABC and EDC are,

BC = 62 feet, DC = 93 feet and DE = 125 feet(given)

And, angles B and D are right angles,

⇒ $\angle ABC\cong \angle EDC$

$\text{Also, } \angle ACB\cong \angle ECD$ ( Vertically opposite angles )

By AA similarity postulate,

$\triangle ABC\sim \triangle EDC$

The sides of similar triangles are in same proportion ,

⇒ $\frac{AB}{ED}=\frac{BC}{DC}$

⇒ $AB \times DC = BC \times ED$

⇒ $AB = \frac{BC.ED}{DC}$

By substituting the values,

We get,

⇒ $AB = \frac{62\times 125}{93}$

⇒ $AB = \frac{7750}{93}=83.\overline{3}\text{ feet}$

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