8. complete the statement.
zgdf ?
a. zedf
b. zdef
c. zdgf
d. zdfe

Let's use variables.
m = number of morning practices
a = number of afternoon practices

m + a = 10 (there are 10 practices total, either morning or afternoon)
5m + 6a = 57 (each morning practice is 5 hours, afternoon ones are 6. multiply by the number of each and you would get the total number of hours ran, 57)

Let's solve using substitution.

m + a = 10
m = 10 - a

Substitute 10 - a for m.

5(10 - a) + 6a = 57
50 - 5a + 6a = 57
50 + a =57
a = 7

Use a = 7 in an earlier equation to find m.

m + a = 10
m + 7 = 10
m = 3

There were 3 morning practices and 7 afternoon practices.